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A vessel of depth $2 \mathrm{~d} \mathrm{~cm}$. is halffilled with a liquid of refractive index $\mu_{1}$ and the upper half with a liquid of refractive index $\mu_{2} .$ The apparent depth of the vessel seen perpendicularly is -
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The correct answer is:
$d\left(\frac{1}{\mu_{1}}+\frac{1}{\mu_{2}}\right)$
$\mathrm{h}^{\prime}=\frac{\mathrm{d}_{1}}{\mu_{1}}+\frac{\mathrm{d}_{2}}{\mu_{2}}=\mathrm{d}\left(\frac{1}{\mu_{1}}+\frac{1}{\mu_{2}}\right)$
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