A water drop is divided into eight equal droplets. The pressure difference between the inner and outer side of the big drop will be

Question

A water drop is divided into eight equal droplets. The pressure difference between the inner and outer side of the big drop will be, Same as for smaller droplet, 1 2 of that for smaller droplet, 1 4 of that for smaller droplet, twice that for smaller droplet

MARKS App · Accepted Answer

When break into eight drop radius of small drop is r = R n 1 3 ⇒ r = R 8 1 3 = R 2 For large drop Δ P 1 = 2 T R For small drop Δ P 2 = 2 T r = 2 T R 2 = 2 2 T R

Search any question & find its solution

Looking for more such questions to practice?