A wave of frequency 500 Hz has a velocity of 350 m s - 1 . The distance between two nearest points on the wave which are 60 ° out of phase with each other will be around

Question

A wave of frequency 500 Hz has a velocity of 350 m s - 1 . The distance between two nearest points on the wave which are 60 ° out of phase with each other will be around, 70 cm, 0.7 m, 12.0 cm, 120.0 cm

MARKS App · Accepted Answer

Given, frequency f = 500 Hz, velocity v = 350 m/s, phase ϕ = 6 0 ∘ By the formula, λ = v f = 3 5 0 5 0 0 = 0.7 m Also we know that Δ x = Δ ϕ λ 2 π = 6 0 × π 1 8 0 × 0.7 2 π ≈ 0.12 metre ≈ 12 cm

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