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A well-cut diamond appears bright because
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The correct answer is:
of its total internal reflection
As we know that, the refractive index $\mu$ of diamond is highest.
And since, $\mu=\frac{1}{\sin \theta_c}$
where, $\theta_C$ is critical angle and least.
So, chances of total internal reflection will be highest inside diamond.
Hence, diamond appears bright.
And since, $\mu=\frac{1}{\sin \theta_c}$
where, $\theta_C$ is critical angle and least.
So, chances of total internal reflection will be highest inside diamond.
Hence, diamond appears bright.
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