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A wheel has angular acceleration of $3.0 \mathrm{rad} / \mathrm{s}^2$ and an initial angular speed of $2.00 \mathrm{rad} / \mathrm{s}$. In a time of 2 s it has rotated through an angle (in radian) of
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10
$\theta=\omega_0 t+\frac{1}{2} \alpha t^2$
Given, $\alpha=3.0 \mathrm{rad} / \mathrm{s}^2, \omega_0=2.0 \mathrm{rad} / \mathrm{s}, t=2 \mathrm{~s}$.
Hence, $\quad \theta=2 \times 2+\frac{1}{2} \times 3 \times(2)^2$ or $\theta=4+6=10 \mathrm{rad}$
Given, $\alpha=3.0 \mathrm{rad} / \mathrm{s}^2, \omega_0=2.0 \mathrm{rad} / \mathrm{s}, t=2 \mathrm{~s}$.
Hence, $\quad \theta=2 \times 2+\frac{1}{2} \times 3 \times(2)^2$ or $\theta=4+6=10 \mathrm{rad}$
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