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A wheel has angular acceleration of 3.0 $\mathrm{rad} / \mathrm{sec}^2$ and an initial angular speed of $2~ \mathrm{rad}/ \mathrm{sec}$. In a time of $2 \mathrm{sec}$ it has rotated through an angle (in radian) of:
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Verified Answer
The correct answer is:
10
Here $\theta=\omega t+\frac{1}{2} t^2$
$\begin{aligned}
& =(2)(2)+\frac{1}{2}(3)(2)^2 \\
& =4+6=10 \mathrm{rad}
\end{aligned}$
$\begin{aligned}
& =(2)(2)+\frac{1}{2}(3)(2)^2 \\
& =4+6=10 \mathrm{rad}
\end{aligned}$
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