Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Open MARKS Web Download App
Search any question & find its solution
Question: Answered & Verified by Expert
A wheel of radius $2 \mathrm{~cm}$ is at rest on the horizontal surface. A point $\mathrm{P}$ on
circumference of the wheel is in contact with the horizontal surface. When the
wheel rolls without slipping on the surface, the displacement of point P after half rotation of wheel is
PhysicsRotational MotionMHT CETMHT CET 2020 (12 Oct Shift 2)
Options:
  • A $2\left(\pi^{2}+2\right)^{\frac{1}{2}} \mathrm{~cm}$
  • B $\left(\pi^{2}+2\right)^{\frac{1}{2}} \mathrm{~cm}$
  • C $\left(\pi^{2}+4\right)^{\frac{1}{2}} \mathrm{~cm}$
  • D $2\left(\pi^{2}+4\right)^{\frac{1}{2}} \mathrm{~cm}$
Solution:
2002 Upvotes Verified Answer
The correct answer is: $2\left(\pi^{2}+4\right)^{\frac{1}{2}} \mathrm{~cm}$
No Solution

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.

Use on iOS or Desktop Download from Google Play