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Question: Answered & Verified by Expert
A whistle emitting a loud sound of frequency $540 \mathrm{~Hz}$ is whirled in a horizontal circle of radius $2 \mathrm{~m}$ and at a constant angular speed of $15 \mathrm{rad} / \mathrm{s}$. The speed of sound is $330 \mathrm{~m} / \mathrm{s}$. The ratio of the highest to the lowest frequency heard by a listener standing at rest at a large distance from the center of the circle is :
PhysicsWaves and SoundKVPYKVPY 2014 (SB/SX)
Options:
  • A $1.0$
  • B $1.1$
  • C $1.2$
  • D $1.4$
Solution:
1503 Upvotes Verified Answer
The correct answer is: $1.2$


$n^{\prime}=n\left[\frac{v-0}{v+v_{s}}\right]$
$n "=n\left[\frac{v}{v+v_{s}}\right]$
$\frac{n^{\prime}}{n^{\prime \prime}}=\frac{v-v_{s}}{v+v_{s}}$
$\frac{n^{\prime}}{n^{\prime \prime}}=\frac{v+v_{s}}{v-v_{s}}=\frac{330+30}{330-30}=\frac{360}{300}=1.2$

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