A whistle producing sound waves of frequencies 9500 Hz and above is approaching a stationary person with speed of v m s - 1 . The velocity of sound in air is 300 m s - 1 . If the person can hear frequencies up to a maximum of 10000 Hz , the maximum value of v up to which he can hear the whistle is

Question

A whistle producing sound waves of frequencies 9500 Hz and above is approaching a stationary person with speed of v m s - 1 . The velocity of sound in air is 300 m s - 1 . If the person can hear frequencies up to a maximum of 10000 Hz , the maximum value of v up to which he can hear the whistle is, 30 m s -1, 15 2 m s -1, 15 2 m s - 1, 15 m s -1

MARKS App · Accepted Answer

ν ' ν = v s v s - v where v s is the velocity of sound in air. 10000 9500 = 300 300 - v ⇒ 300 - v = 285 ⇒ v = 15 m s - 1

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