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A white crystalline salt A reacts with dilute $\mathrm{HCl}$ to liberate a suffocating gas B and also forms a yellow precipitate. The gas B turns potassium dichromate acidified with dilute $\mathrm{H}_{2} \mathrm{SO}_{4}$ to a green coloured solution C. A, B and C are respectively
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$\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}, \mathrm{SO}_{2}, \mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}$
Gas B turns the colour of acidified $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ green thus it is $\mathrm{SO}_{2}$ and $\mathrm{SO}_{2}$ is obtained along with yellow precipitate when thio sulphate is treated with dilute acids. Thus, $\mathrm{A}$ is $\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3}$, B is $\mathrm{SO}_{2}$ and $\mathrm{C}$ is $\mathrm{Cr}_{2}\left(\mathrm{SO}_{4}\right)_{3}$.
The reactions are as follows
The reactions are as follows
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