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Question: Answered & Verified by Expert

A wire carrying current I is bent in the shapeABCDEFA as shown, where rectangle ABCDA and ADEFA are perpendicular to each other. If the sides of the rectangles are of lengths a and b, then the magnitude and direction of magnetic moment of the loop ABCDEFA is :

PhysicsMagnetic Effects of CurrentJEE MainJEE Main 2020 (02 Sep Shift 2)
Options:
  • A 2abI along j^2+k^2
  • B abI along j^2+k^2
  • C 2abI along j^5+2k^5
  • D abI along j^5+k^5
Solution:
1114 Upvotes Verified Answer
The correct answer is: 2abI along j^2+k^2

Loop ABCD

M1=(abI)(k^)
For Loop DEFA M2=(abI)(j^)
M=M1+M2;M=(abI)(j^+k^)
2abI along j^2+k^2.

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