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A wire fixed at the upper end stretches by length by applying a force F. The work done in stretching is
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Verified Answer
The correct answer is:
$\mathrm{F} \ell / 2$
$\mathrm{F} \ell / 2$
Work done $=\frac{1}{2} \mathrm{kx}^2=\frac{1}{2} \mathrm{k} \ell^2$ where $\ell$ is the total extensions.
$$
=\frac{1}{2}(\mathrm{k} \ell) \ell=\frac{1}{2} \mathrm{~F} \ell
$$
$$
=\frac{1}{2}(\mathrm{k} \ell) \ell=\frac{1}{2} \mathrm{~F} \ell
$$
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