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Question: Answered & Verified by Expert
A wire is bent to form a semicircle of radius a . The wire rotates about its one end with angular velocity ω . Axis of rotation being perpendicular to the plane of the semicircle. In the space, a uniform magnetic field of induction B exists along the axis of rotation, as shown in figure. Then

PhysicsElectromagnetic InductionNEET
Options:
  • A potential difference between P and Q is equal to 2Bωa2
  • B potential difference between P and Q is equal to 2π2Bωa2
  • C P is at higher potential than Q
  • D none of these
Solution:
2585 Upvotes Verified Answer
The correct answer is: potential difference between P and Q is equal to 2Bωa2
e=12Bωl2

e=12Bω2a2

e = 2Bωa2

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