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Question: Answered & Verified by Expert
A wire is bent to form a semicircle of the radius a. The wire rotates about its one end with angular velocity ω. Axis of rotation is perpendicular to the plane of the semicircle. In the space, a uniform magnetic field of induction B exists along the axis of rotation as shown in the figure. Then -

PhysicsElectromagnetic InductionNEET
Options:
  • A The potential difference between P and Q is equal to 2Bωa2
  • B potential difference between P and Q is equal to 2π2Bωa2
  • C P is at higher than Q
  • D None of these
Solution:
2589 Upvotes Verified Answer
The correct answer is: The potential difference between P and Q is equal to 2Bωa2
When wire of length l rotates with angular speed omega in external magnetic field then emf is induced in that wire.

e=12Bωl2=12Bω2a2=2Bωa2

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