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A wire is suspended from the ceiling and stretched under the action of a weight $F$ suspended from its other end. The force exerted by the ceiling on it is equal and opposite to the weight.
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Verified Answer
The correct answers are:
Tensile stress at any cross-section $A$ of the wire is $F / A$
,
Tension at any cross-section $A$ of the wire is $F$
Tensile stress at any cross-section $A$ of the wire is $F / A$
,
Tension at any cross-section $A$ of the wire is $F$
As the given diagram showns, The forces at each cross-section is $F$. We know that,
$$
\text { Stress }=\frac{\text { Tension }}{\text { Area }}=\frac{F}{A}
$$
Tension $=$ Applied Force $=F$ So, tension is balanced by force $F$. Hence, $(T=F)$.
$$
\text { Stress }=\frac{\text { Tension }}{\text { Area }}=\frac{F}{A}
$$
Tension $=$ Applied Force $=F$ So, tension is balanced by force $F$. Hence, $(T=F)$.
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