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Question: Answered & Verified by Expert
A wire of cross-sectional area $3 \mathrm{~mm}^2$ is first stretched between two fixed points at a temperature of $20^{\circ} \mathrm{C}$. Determine the tension when the temperature falls to $10^{\circ} \mathrm{C}$. Coefficient of linear expansion $\alpha=10^{-5}{ }^{\circ} \mathrm{C} \mathrm{C}^{-1}$ and $Y=2 \times 10^{11} \mathrm{~N} / \mathrm{m}^2$
PhysicsMechanical Properties of SolidsJEE Main
Options:
  • A $20 \mathrm{~N}$
  • B $30 \mathrm{~N}$
  • C $60 \mathrm{~N}$
  • D $120 \mathrm{~N}$
Solution:
1521 Upvotes Verified Answer
The correct answer is: $60 \mathrm{~N}$
$F=Y A \alpha \Delta t=2 \times 10^{11} \times 3 \times 10^{-6} \times 10^{-5} \times(20-10)=60 \mathrm{~N}$

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