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Question: Answered & Verified by Expert
A wire of length 10 m is subjected to a force of 100 N along its length and hence the lateral strain produced is 0.01×10-3 m. The Poisson's ratio was found to be 0.4. If the area of cross-section of wire is 0.025 m2, its Young's modulus will be
PhysicsMechanical Properties of SolidsNEET
Options:
  • A 1.6×108 Nm-2
  • B 2.5×1010 Nm-2
  • C 1.25×1011Nm-2
  • D 16×109Nm-2
Solution:
2720 Upvotes Verified Answer
The correct answer is: 1.6×108 Nm-2
Poisson's ratio =Lateral strainLongitudinal strain

ie,   0.4=0.01×10-3lL

or Ll=0.40.01×10-3=4×104

Young's modulus

Y=FLAl

=1000.025×4×104=1.6×108Nm-2

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