Length of the wire $l$ when bent becomes circumference of the loop, whose radius is given by $R=\frac{l}{2\pi }=\frac{314}{100\left(2\times 3.14\right)}=\frac{1}{2} \mathrm{m}$

Magnetic moment of the coil is $M=IA$

$=14\times \pi R^2$

$=14\times \left(3.14\right)\times \frac{1}{4}$

$=10.99\approx 11.00 \mathrm{A}-{\mathrm{m}}^2$