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A wire of length L and 3 identical cells, of negligible internal resistance, are connected in series. Due to the current, the temperature of the wire is raised by ΔT in a time t. A number of N similar cells are now connected in series with a wire of the same material and area of cross-section but of length 2L. The temperature of the wire is raised by the same amount ΔT in the same time. Find the value of N.

PhysicsCurrent ElectricityJEE Main
Solution:
1300 Upvotes Verified Answer
The correct answer is: 6
In the first case

         3E2Rt=msΔT        ... (ii)

 When the length of the wire is doubled, resistance and mass both are doubled. Therefore, in the second case,

        NE22Rt=2msΔT        ... (ii)

 Dividing Eq.(ii) by (i) we get

        N218=2

or   N2=36

or   N=6

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