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A wire of length 'L' and radius ' $\mathrm{r}$ ' is loaded with a weight ' $\mathrm{Mg}$ '. If ' $\mathrm{Y}$ ' and ' $\sigma$ ' denote the Young's modulus and poisson's ratio of the material of the wire respectively, then the decrease in the radius of the wire $(\Delta \mathrm{r})$ is given by
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The correct answer is:
$\frac{\mathrm{Mg} \sigma}{\pi \mathrm{rY}}$
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