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A wire of resistance $12 \mathrm{ohms}$ per metre is bent to form a complete circle of radius $10 \mathrm{~cm}$. The resistance between its two diametrically opposite points, A and B as shown in the figure, is :
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Verified Answer
The correct answer is:
$0.6 \pi \Omega$
Total resistance of wire $=12 \Omega \times 2 \pi \times 10^{-1}$
$$
=2.4 \pi
$$
Resistance of each half $=\frac{2.4 \pi}{2}=1.2 \pi$
and as about diameter both parts are in parallel
$$
\text { Req. }=\frac{1.2 \pi}{2}=0.6 \pi \Omega
$$
$$
=2.4 \pi
$$
Resistance of each half $=\frac{2.4 \pi}{2}=1.2 \pi$
and as about diameter both parts are in parallel
$$
\text { Req. }=\frac{1.2 \pi}{2}=0.6 \pi \Omega
$$
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