A wire of resistance 18 Ω is divided into three equal parts. These parts are connected as sides of a triangle, the equivalent resistance of any two corners of the triangle will be

Question

A wire of resistance 18 Ω is divided into three equal parts. These parts are connected as sides of a triangle, the equivalent resistance of any two corners of the triangle will be, 18 Ω, 9 Ω, 6 Ω, 4 Ω

MARKS App · Accepted Answer

To find equivalent resistance across BC, AB and AC is in series R ′ = 6 + 6 = 12 Ω 12 Ω a n d 6 Ω is in parallel Total resistance, R = 12 × 6 12 + 6 R = 72 18 = 4 Ω

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