Search any question & find its solution
Question:
Answered & Verified by Expert
A wire of Young's modulus $1 \cdot 6 \times 10^{12} \mathrm{~N} / \mathrm{m}^{2}$ is stretched by a force so as to produce a strain of $2 \times 10^{-4}$. The energy density of the wire is
Options:
Solution:
1330 Upvotes
Verified Answer
The correct answer is:
$3 \cdot 2 \times 10^{4} \mathrm{~J} / \mathrm{m}^{3}$
Energy $=1 / 2 \times Y \times(\text { Strain })^{2}$
$=1 / 2 \times 1.6 \times 10^{12} \times 4^{2} \times 10^{-8}$
$=3.2 \times 10^{4}$.
$=1 / 2 \times 1.6 \times 10^{12} \times 4^{2} \times 10^{-8}$
$=3.2 \times 10^{4}$.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.