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Question: Answered & Verified by Expert
A wire, suspended vertically from one of its ends, is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm. The elastic energy (in J) stored in the wire is
PhysicsWork Power EnergyJEE Main
Solution:
1429 Upvotes Verified Answer
The correct answer is: 0.1
U=12×F×l=12×200×10-3=0.1 J

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