A wire suspended vertically from one of its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm . Then the elastic energy stored in the wire is

Question

A wire suspended vertically from one of its ends is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1 mm . Then the elastic energy stored in the wire is, 0 . 2 J, 10 J, 20 J, 0 . 1 J

MARKS App · Accepted Answer

Elastic energy per unit volume = 1 2 × stress × strain ∴ Elastic energy = 1 2 × stress × strain × volume = 1 2 × F A × Δ L L × AL = 1 2 F Δ L = 1 2 × 200 × 10 - 3 =0.1 J

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