A woman with two genes (one on each X -chromosome) for haemophilia and one gene for colour blindness on the X-chromosome marries a normal man. How will the progeny be?

Question

A woman with two genes (one on each X -chromosome) for haemophilia and one gene for colour blindness on the X-chromosome marries a normal man. How will the progeny be?, All sons and daughters are haemophilic and colourblind, Haemophilic and colourblind daughters, 50% haemophilic colourblind sons and 50% haemophilic sons, 50% haemophilic daughters and 50% colourblind daughters

MARKS App · Accepted Answer

Haemophilia and colour blindness both are recessive X-linked traits. They express in males when present in single copy (heterozygous) but in females, they express only when present in homozygous condition. Results (a) 50% sons are colourblind and haemophilic. (b) 50% sons are haemophilic only. (c) 50% daughters are carrier for colour blindness and haemophilia. (d) 50% daughters are carrier for haemophilia only.

Search any question & find its solution

Looking for more such questions to practice?