A wooden block of density 0 . 5 g / cc is tied to a string. The other end of the string is fixed to the bottom of a tank. The tank is filled with a liquid of density 1 g / cc . If the tension of the string is 20 N , then the mass of the block is (Take g = 10 m / s 2 )

Question

A wooden block of density 0 . 5 g / cc is tied to a string. The other end of the string is fixed to the bottom of a tank. The tank is filled with a liquid of density 1 g / cc . If the tension of the string is 20 N , then the mass of the block is (Take g = 10 m / s 2 ), 1 kg, 2 kg, 3 kg, 0 . 5 kg

MARKS App · Accepted Answer

At equilibrium, tension in the string must be equal to apparent weight of the block in liquid, T = W A p p a r e n t ⇒ T = F B - W ⇒ T = ρ l V g - ρ s V g On putting all the corresponding values, we have ⇒ 20 = 1000 - 500 V × 10 ⇒ V = 20 5000 = 1 250 m 3 Mass of the block is, m = ρ s V ⇒ m = 500 × 1 250 = 2 kg

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