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A Zener diode has a breakdown voltage of \(9.1 \mathrm{~V}\) with a maximum power dissipation of \(364 \mathrm{~mW}\). What is the maximum current that the diode can withstand ?
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Verified Answer
The correct answer is:
\(0.04 \mathrm{~A}\)
Applying formula
\(\text {Maximum current }=\frac{364 \times 10^{-3}}{9.1}=0.04 \mathrm{~A}\)
\(\text {Maximum current }=\frac{364 \times 10^{-3}}{9.1}=0.04 \mathrm{~A}\)
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