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A Zener diode, having breakdown voltage equal to $15 \mathrm{~V}$ is used in a voltage regulator circuit shown in figure. The current through the diode is
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Verified Answer
The correct answer is:
$5 \mathrm{~mA}$
For $\mathrm{R}=1 \mathrm{k} \Omega$
$\begin{array}{l}
\mathrm{i}_{1}=\frac{15}{1} \mathrm{~mA}=15 \mathrm{~mA} \\
\mathrm{R}=250 \Omega \\
\mathrm{i}_{250}=\frac{20-15}{250}=\frac{5}{250}=20 \mathrm{~mA} \\
\mathrm{i}_{\mathrm{Zener}}=20-15=5 \mathrm{~mA}
\end{array}$
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