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ABC is a triangle. Forces $\vec{P}, \vec{Q}, \vec{R}$ acting along $I A, I B$ and $I C$ respectively are in equilibrium, where $I$ is the incentre of $\triangle A B C$. Then $P: Q: R$ is
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Verified Answer
The correct answer is:
$\cos \frac{\mathrm{A}}{2}: \cos \frac{\mathrm{B}}{2}: \cos \frac{\mathrm{C}}{2}$
$\cos \frac{\mathrm{A}}{2}: \cos \frac{\mathrm{B}}{2}: \cos \frac{\mathrm{C}}{2}$
Using Lami's Theorem
$$
\therefore P: Q: R=\cos \frac{A}{2}: \cos \frac{B}{2}: \cos \frac{C}{2} \text {. }
$$
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