ABC is an equilateral triangle. Charges + q are placed at each corner. The electric intensity at 0 will be

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$\mathrm{ABC}$ is an equilateral triangle. Charges ${ }^{+} q$ are placed at each corner. The electric intensity at 0 will be

PhysicsElectrostaticsJEE Main

Options:

A $\frac{1}{4 \pi \varepsilon_0} \frac{q}{r^2}$
B $\frac{1}{4 \pi \varepsilon_0} \frac{q}{r}$
C Zero
D $\frac{1}{4 \pi \varepsilon_0} \frac{3 q}{r^2}$

Solution:

1991 Upvotes Verified Answer

The correct answer is: Zero

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