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$\mathrm{ABCD}$ is a parallelogram. If $\overrightarrow{\mathrm{AB}}=\overrightarrow{\mathrm{a}}, \overrightarrow{\mathrm{BC}}=\overrightarrow{\mathrm{b}}$, then what is
$\overrightarrow{\mathrm{BD}}$ equal to ?
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$\overrightarrow{\mathrm{BD}}$ equal to ?
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The correct answer is:
$\quad-\overrightarrow{\mathrm{a}}+\overrightarrow{\mathrm{b}}$
$\overrightarrow{\mathrm{BD}}=-\overrightarrow{\mathrm{a}}+\overrightarrow{\mathrm{b}}$
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