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Question: Answered & Verified by Expert
About 5% of the power of a 100 W light bulb is converted to visible radiation. The average intensity of visible radiation at a distance of 1 m from the bulb:
PhysicsWave OpticsNEET
Options:
  • A 0.4 W m-2
  • B 0.5 W m-2
  • C 0.6 W m-2
  • D 0.8 W m-2
Solution:
2481 Upvotes Verified Answer
The correct answer is: 0.4 W m-2
Visible power = 5 W

Average intensity of radiation at 1 m

=power4πr2=54×π×1=0.4Wm-2

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