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Above the curie temperature the susceptibility of a ferromagnetic substance varies
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Verified Answer
The correct answer is:
inversely as the absolute temperature.
$\chi \propto \frac{1}{\mathrm{~T}}$ (Theory question)
15. Gain in kinetic energy $=$ loss in potential energy
$$
\begin{aligned}
& \frac{1}{2} \mathrm{~m}\left(1+\frac{\mathrm{k}^{2}}{\mathrm{R}^{2}}\right) \mathrm{V}^{2}=\mathrm{mgh} \\
& \frac{1}{2}\left(1+\frac{1}{2}\right) \mathrm{V}^{2}=\mathrm{gh} \\
\therefore & \frac{3}{4} \mathrm{~V}^{2}=\mathrm{gh} \\
\therefore & \mathrm{h}=\frac{3 \mathrm{~V}^{2}}{4 \mathrm{~g}}
\end{aligned}
$$
15. Gain in kinetic energy $=$ loss in potential energy
$$
\begin{aligned}
& \frac{1}{2} \mathrm{~m}\left(1+\frac{\mathrm{k}^{2}}{\mathrm{R}^{2}}\right) \mathrm{V}^{2}=\mathrm{mgh} \\
& \frac{1}{2}\left(1+\frac{1}{2}\right) \mathrm{V}^{2}=\mathrm{gh} \\
\therefore & \frac{3}{4} \mathrm{~V}^{2}=\mathrm{gh} \\
\therefore & \mathrm{h}=\frac{3 \mathrm{~V}^{2}}{4 \mathrm{~g}}
\end{aligned}
$$
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