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Question: Answered & Verified by Expert
According to Bohr's atomic model, the radius of the orbit is directly proportional to
PhysicsAtomic PhysicsJEE Main
Options:
  • A $n^2$
  • B $1 / n^2$
  • C $1 / n$
  • D $n$
Solution:
2820 Upvotes Verified Answer
The correct answer is: $n^2$
The radius of $n$th orbit is $r_n=0.53 \times \frac{n^2}{Z} A^{\circ}$. Here, $Z$ is atomic number which is constant for atom.Hence, the radius of stable orbits is proportional to $\mathrm{n}^2$

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