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According to Bohr's theory, the angular momentum of an electron in $5^{\text {th }}$ orbit is
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$2.5 \frac{\mathrm{h}}{\pi}$
$2.5 \frac{\mathrm{h}}{\pi}$
$\begin{aligned} \mathrm{mvr} & =\frac{\mathrm{nh}}{2 \pi} \\ & =\frac{5 \mathrm{~h}}{2 \pi}=2.5 \frac{\mathrm{h}}{\pi}\end{aligned}$
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