According to Bohr's theory, the angular momentum of an electron revolving in second orbit of hydrogen atom will be

Question

According to Bohr's theory, the angular momentum of an electron revolving in second orbit of hydrogen atom will be, $ 2 \pi h $, $ \pi h $, $ \frac{h}{\pi} $, $ \frac{2 h}{\pi} $

MARKS App · Accepted Answer

Angular momentum = n h 2 π = 2 h 2 π = h π

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