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Question: Answered & Verified by Expert
According to Graham's law at a given temperature, the ratio of the rates of diffusion $r_A / r_B$ of gases $A$ and $B$ is given by (where $P$ and $M$ are the pressures and molecular weights of gases $A$ and $B$ respectively)
ChemistryStates of MatterJEE Main
Options:
  • A $\left(P_A / P_B\right)\left(M_A / M_B\right)^{1 / 2}$
  • B $\left(M_A / M_B\right)\left(P_A / P_B\right)^{1 / 2}$
  • C $\left(P_A / P_B\right)\left(M_B / M_A\right)^{1 / 2}$
  • D $\left(M_A / M_B\right)\left(P_B / P_A\right)^{1 / 2}$
Solution:
1367 Upvotes Verified Answer
The correct answer is: $\left(P_A / P_B\right)\left(M_B / M_A\right)^{1 / 2}$
$\therefore(c)\left(P_A / P_B\right)\left(M_B / M_A\right)^{1 / 2}$

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