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According to Hardy-Weinberg’s principle, if allele one is denoted as ‘A’ and allele two as ‘a’ and their frequencies are denoted by p and q, and if random mating occurs. The frequency of heterozygous individual would be:

BiologyEvolutionNEET
Options:
  • A

    2pq

  • B

      q 2

  • C

    pq

  • D

       p 2

Solution:
1679 Upvotes Verified Answer
The correct answer is:

2pq

Hardy-Weinberg’s principle states that the allele frequency of a population remains constant from generation to generation unless specific disturbing influences are introduced. This is called genotype equilibrium.

A single locus with two alleles: allele one is denoted as ‘A’ and allele two as ‘a’ and their frequencies are denoted by p and q;

frequency ( A ) = p
frequency ( a ) = q

And, p + q = 1 .

If mating is random, then new individuals will have:

frequency ( AA ) = p 2 for the AA homozygotes in the population,

frequency ( aa ) =  q 2  for the aa homozygotes, and

frequency ( Aa ) = 2pq for the Aa heterozygotes.

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