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According to "molecular orbital theory", which among the following diatomic molecules only has $\pi$-bonds?
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Verified Answer
The correct answer is:
$\mathrm{C}_2$
Molecular orbital configuration of $\mathrm{C}_2$ is
$\sigma l s^2 \sigma * 1 s^2 \sigma 2 s^2 \sigma * 2 s^2 \pi 2 p_x^2=\pi 2 p_y^2$
So, $\mathrm{C}_2$ molecule contains only $\pi$-bonds.
$\sigma l s^2 \sigma * 1 s^2 \sigma 2 s^2 \sigma * 2 s^2 \pi 2 p_x^2=\pi 2 p_y^2$
So, $\mathrm{C}_2$ molecule contains only $\pi$-bonds.
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