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According to Raoult's law mole fraction of solute in solution is given by formula
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The correct answer is:
$\frac{\Delta \mathrm{P}}{\mathrm{P}_1^0}$
$P_1=$ Vapour pressure of solution
$\mathrm{P}_1^0=$ Vapour pressure of pure solvent
Mole fraction of solute $=\frac{\mathrm{P}_1^0-\mathrm{P}_1}{\mathrm{P}_1^0}=\frac{\Delta \mathrm{P}}{\mathrm{P}_1^0}$
$\mathrm{P}_1^0=$ Vapour pressure of pure solvent
Mole fraction of solute $=\frac{\mathrm{P}_1^0-\mathrm{P}_1}{\mathrm{P}_1^0}=\frac{\Delta \mathrm{P}}{\mathrm{P}_1^0}$
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