Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
According to Valence Bond Theory, the number of unpaired electrons present in MnCl63-, Fe(CN)63- and CoC2O43-, respectively, are
ChemistryCoordination CompoundsTS EAMCETTS EAMCET 2021 (05 Aug Shift 1)
Options:
  • A 0 ; 5 ; 0
  • B 4 ; 3 ; 2
  • C 4 ; 1 ; 0
  • D 5 ; 4 ; 3
Solution:
1729 Upvotes Verified Answer
The correct answer is: 4 ; 1 ; 0

In MnCl63- oxidation state of manganese is +3

Mn+3, electronic configuration is Ar3d44s0, due to the presence of weak field ligand Cl-pairing of electrons do not occur, so the number of unpaired electrons are 4.

In FeCN63- oxidation state of Fe is +3,

Fe+3 electronic configuration is  Ar3d54s0

Due to the presence of strong field pairing of electrons takes place but one electron remains unpaired, t2g5 configuration is seen.

InCoC2O43-, cobalt shows +3 oxidation state and electronic configuration, Ar3d64s0.

As C2O42- behaves as a strong field ligand in complexes with cobalt, paring of electrons takes place and no unpaired electrons are left in this case.

 

 

 

 

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.