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Acetic acid is treated with \( \mathrm{Ca}(\mathrm{OH})_{2} \) and the product so obtained is subjected to dry
distillation. The final product is
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distillation. The final product is
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The correct answer is:
propanone
When acetic acid reacts with slaked lime, calcium acetate is formed, which on dry distillation produces ketone.
\( 2 \mathrm{CH}_{3} \mathrm{COOH}+\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{Ca}+2 \mathrm{H}_{2} \mathrm{O} \)
\( 2 \mathrm{CH}_{3} \mathrm{COOH}+\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2} \mathrm{Ca}+2 \mathrm{H}_{2} \mathrm{O} \)
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