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Acetophenone cannot be prepared easily starting from
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The correct answer is:
\( \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3} \)
Acetophenone cannot be prepared easily starting from \( \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3} \), because, in toluene the substitution will takes place
at different positions which will not form acetophenone.
at different positions which will not form acetophenone.
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