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Addition of excess of \( \mathrm{AgNO}_{3} \) to an aqueous solution of \( 1 \) mole of \( \mathrm{PdCl}_{2} \cdot 4 \mathrm{NH}_{3} \) gives \( 2 \)
moles of \( \mathrm{AgCl} \). The conductivity of this solution corresponds to
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moles of \( \mathrm{AgCl} \). The conductivity of this solution corresponds to
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Verified Answer
The correct answer is:
\( 1: 2 \) electrolyte
(A)
\( \left[\mathrm{Pd}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{2} \rightarrow\left[\mathrm{Pd}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}+2 \mathrm{Cl}^{-} \)
It is \( 1: 2 \mathrm{i} . \mathrm{e}, A B_{2} \) type of electrolyte.
\( \left[\mathrm{Pd}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{2} \rightarrow\left[\mathrm{Pd}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}+2 \mathrm{Cl}^{-} \)
It is \( 1: 2 \mathrm{i} . \mathrm{e}, A B_{2} \) type of electrolyte.
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