AlCl 3 in water at pH 7 forms, tetrahedral Al ( OH ) 4 − ions, octahedral Al ( OH ) 6 3 − ions, square planar Al ( OH ) 4 − ions, octahedral Al ( OH 2 ) 6 3 + ions

AlCl 3 form [ Al ( H 2 O ) 6 ] 3 + in water due to acidic medium ( pH 7 ) . $ AlCl 3 + 6 H 2 O ⟶ [ Al ( H 2 O ) 6 ] 3 + + 3 Cl ⊖ $

AlCl 3 in water at pH 7 forms

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$\mathrm{AlCl}_3$ in water at $\mathrm{pH} < 7$ forms

Chemistryp Block Elements (Group 13 & 14)TS EAMCETTS EAMCET 2018 (05 May Shift 1)

Options:

A tetrahedral $\mathrm{Al}(\mathrm{OH})_4^{-}$ions
B octahedral $\mathrm{Al}(\mathrm{OH})_6^{3-}$ ions
C square planar $\mathrm{Al}(\mathrm{OH})_4^{-}$ions
D octahedral $\mathrm{Al}\left(\mathrm{OH}_2\right)_6^{3+}$ ions

Solution:

1408 Upvotes Verified Answer

The correct answer is: octahedral $\mathrm{Al}\left(\mathrm{OH}_2\right)_6^{3+}$ ions

$\mathrm{AlCl}_3$ form $\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$ in water due to acidic medium $(\mathrm{pH} < 7)$.
$$
\mathrm{AlCl}_3+6 \mathrm{H}_2 \mathrm{O} \longrightarrow\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}+3 \mathrm{Cl}^{\ominus}
$$

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