Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Although $\mathrm{Cr}^{3+}$ and $\mathrm{Co}^{2+}$ ions have same number of unpaired electrons but the magnetic moment of $\mathrm{Cr}^{3+}$ is 3.87 $\mathrm{BM}$ and that of $\mathrm{Co}^{2+}$ is $4.87 \mathrm{BM}$, Why?
Chemistryd and f Block Elements
Solution:
2102 Upvotes Verified Answer
Magnetic moment of any metal ion can be decided on the basis of spin as well as orbital contribution of electron. Due to symmetrical electronic configuration, there is no orbital contribution in $\mathrm{Cr}^{3+}$ ion. However appreciable orbital contribution takes place in $\mathrm{Co}^{2+}$ ion.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.