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Aluminium chloride exists as dimer, $\mathrm{Al}_2 \mathrm{Cl}_6$ in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives
Chemistryp Block Elements (Group 13 & 14)JEE Main
Options:
  • A $\left[\mathrm{Al} (\mathrm{OH})_5\right]^{3-}+3 \mathrm{HCl}$
  • B $\left[\mathrm{Al} \left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}+3 \mathrm{Cl}^{-}$
  • C $\mathrm{Al}^{3+}+3 \mathrm{Cl}^{-}$
  • D $\mathrm{Al}_2 \mathrm{O}_3+6 \mathrm{HCl}$
Solution:
2392 Upvotes Verified Answer
The correct answer is: $\mathrm{Al}_2 \mathrm{O}_3+6 \mathrm{HCl}$
$\mathrm{Al}_2 \mathrm{Cl}_6+12 \mathrm{H}_2 \mathrm{O} \rightleftharpoons 2\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}+6 \mathrm{Cl}^{-}$

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