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Aluminium chloride in acidified aqueous solution gives a complex ion ' $X^{\prime}$. The hybridisation of central atom in $X$ is
ChemistryChemical Bonding and Molecular StructureAP EAMCETAP EAMCET 2022 (07 Jul Shift 2)
Options:
  • A $s p^3$
  • B $s p^2 d$
  • C $d^2 s p^3$
  • D $s p^3 d^2$
Solution:
1707 Upvotes Verified Answer
The correct answer is: $s p^3 d^2$
If aluminium chloride in acidified aqueous solution forms a complex $\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}$ that is hexa aquaaluminium (III) ion, and $\mathrm{Al}$ is in $s p^3 d^2$ hybridisation.
$$
\mathrm{AlCl}_3+6 \mathrm{H}_2 \mathrm{O} \longrightarrow\left[\mathrm{Al}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{3+}+3 \mathrm{Cl}^{-}
$$

Electronic configuration of $\mathrm{Al}^{3+}$

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