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Ammonia on reaction with chlorine forms an explosive $\mathrm{NCl}_3$. What is the mole ratio of $\mathrm{NH}_3$ and $\mathrm{Cl}_2$ required for this reaction?
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The correct answer is:
$1: 3$
The balanced equation is
$$
\mathrm{NH}_3+3 \mathrm{Cl}_2 \longrightarrow \mathrm{NCl}_3+3 \mathrm{HCl}
$$
Thus, the ratio of $\mathrm{NH}_3$ to $3 \mathrm{Cl}_2$ is $1: 3$.
$$
\mathrm{NH}_3+3 \mathrm{Cl}_2 \longrightarrow \mathrm{NCl}_3+3 \mathrm{HCl}
$$
Thus, the ratio of $\mathrm{NH}_3$ to $3 \mathrm{Cl}_2$ is $1: 3$.
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